Question

(\frac{-15w^{0}u^{-1}}{5u^{3}})

Explanation:

Step1: Simplify $w^0$

Any non-zero number to the 0 power is 1, so $w^0=1$. The expression becomes $\frac{-15 \times 1 \times u^{-1}}{5u^3} = \frac{-15u^{-1}}{5u^3}$

Step2: Simplify the constant coefficients

Divide -15 by 5: $\frac{-15}{5} = -3$. The expression becomes $-3 \times \frac{u^{-1}}{u^3}$

Step3: Combine the $u$ terms

Use exponent rule $\frac{u^a}{u^b}=u^{a-b}$. Here $a=-1$, $b=3$, so $u^{-1-3}=u^{-4}$. The expression becomes $-3u^{-4}$

Step4: Rewrite with positive exponent

$u^{-4}=\frac{1}{u^4}$, so the expression is $-\frac{3}{u^4}$

Answer:

$-\frac{3}{u^4}$