Question

1. a(-8a² + 2a + 4) + 3(6a² - 4)

Explanation:

Step1: Distribute terms outside parentheses

$a(-8a^2 + 2a + 4) = -8a^3 + 2a^2 + 4a$
$3(6a^2 - 4) = 18a^2 - 12$

Step2: Combine all expanded terms

$-8a^3 + 2a^2 + 4a + 18a^2 - 12$

Step3: Combine like terms

$-8a^3 + (2a^2 + 18a^2) + 4a - 12$

Answer:

$-8a^3 + 20a^2 + 4a - 12$