QUESTION IMAGE
Question
- $x^{2}-x-20$
- $9x^{2}-1$
- $10x^{2}+15x$
- $4x^{3}+12x^{2}+8x$
- $2x^{2}+14x+20$
- $-2x^{3}+18x$
- $16x^{4}-1$
- $x^{2}-10x+21$
- $x^{2}+5x-50$
10) Step1: Find two factors of -20
Find two numbers that multiply to $-20$ and add to $-1$: $-5$ and $4$.
10) Step2: Factor the quadratic
$x^2 - x - 20 = (x - 5)(x + 4)$
11) Step1: Recognize difference of squares
$9x^2 - 1 = (3x)^2 - (1)^2$
11) Step2: Apply difference of squares rule
$a^2 - b^2 = (a-b)(a+b)$, so $(3x - 1)(3x + 1)$
12) Step1: Factor out greatest common factor
GCF of $10x^2$ and $15x$ is $5x$.
$10x^2 + 15x = 5x(2x + 3)$
13) Step1: Factor out GCF first
GCF of $4x^3, 12x^2, 8x$ is $4x$.
$4x^3 + 12x^2 + 8x = 4x(x^2 + 3x + 2)$
13) Step2: Factor the quadratic
Find factors of 2 that add to 3: 1 and 2.
$4x(x + 1)(x + 2)$
14) Step1: Factor out GCF
GCF of $2x^2, 14x, 20$ is $2$.
$2x^2 + 14x + 20 = 2(x^2 + 7x + 10)$
14) Step2: Factor the quadratic
Find factors of 10 that add to 7: 2 and 5.
$2(x + 2)(x + 5)$
15) Step1: Factor out GCF
GCF of $-2x^3$ and $18x$ is $-2x$.
$-2x^3 + 18x = -2x(x^2 - 9)$
15) Step2: Factor difference of squares
$x^2 - 9 = x^2 - 3^2$, so $-2x(x - 3)(x + 3)$
16) Step1: Recognize difference of squares
$16x^4 - 1 = (4x^2)^2 - (1)^2$
16) Step2: Apply difference of squares rule
$(4x^2 - 1)(4x^2 + 1)$
16) Step3: Factor remaining square
$4x^2 -1 = (2x)^2 -1^2$, so $(2x - 1)(2x + 1)(4x^2 + 1)$
17) Step1: Find factors of 21
Find two numbers that multiply to 21 and add to $-10$: $-3$ and $-7$.
17) Step2: Factor the quadratic
$x^2 - 10x + 21 = (x - 3)(x - 7)$
18) Step1: Find factors of -50
Find two numbers that multiply to $-50$ and add to 5: $10$ and $-5$.
18) Step2: Factor the quadratic
$x^2 + 5x - 50 = (x + 10)(x - 5)$
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