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Question
if \\(\int_{4}^{-10} g(x) dx = -3\\) and \\(\int_{4}^{6} g(x) dx = 5\\), then \\(\int_{-10}^{6} g(x) dx =\\) \\(\boldsymbol{a}\\) \\(-8\\) \\(\boldsymbol{b}\\) \\(-2\\) \\(\boldsymbol{c}\\) \\(2\\) \\(\boldsymbol{d}\\) \\(8\\)
Step1: Reverse integral limits sign
$\int_{4}^{-10} g(x)dx = -\int_{-10}^{4} g(x)dx = -3 \implies \int_{-10}^{4} g(x)dx = 3$
Step2: Split target integral
$\int_{-10}^{6} g(x)dx = \int_{-10}^{4} g(x)dx + \int_{4}^{6} g(x)dx$
Step3: Substitute known values
$\int_{-10}^{6} g(x)dx = 3 + 5$
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