QUESTION IMAGE
Question
- find the value of x for which abcd must be a parallelogram.
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Step1: Recall parallelogram property
In a parallelogram, opposite - sides are equal. So, if \(ABCD\) is a parallelogram, then \(BC = AD\).
We have \(BC=6 + 3x\) and \(AD=x + 14\).
Set up the equation \(6 + 3x=x + 14\).
Step2: Solve the equation for \(x\)
Subtract \(x\) from both sides of the equation:
\(6+3x - x=x + 14 - x\), which simplifies to \(6 + 2x=14\).
Then subtract 6 from both sides: \(6+2x - 6=14 - 6\), getting \(2x = 8\).
Divide both sides by 2: \(\frac{2x}{2}=\frac{8}{2}\), so \(x = 4\).
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