QUESTION IMAGE
Question
- (7x - 23)° 49° (3x)° (11y - 1)° l m
To solve for \( x \) and \( y \), we analyze the angles formed by intersecting lines.
Step 1: Solve for \( x \)
The angles \( 49^\circ \), \( (3x)^\circ \), and \( (7x - 23)^\circ \) are related such that the sum of angles on a straight line is \( 180^\circ \). However, we can also use the property of vertical angles or supplementary angles. Notice that \( (7x - 23)^\circ \) and \( (3x + 49)^\circ \) are supplementary (they form a linear pair). Wait, actually, looking at the diagram, the angle \( (7x - 23)^\circ \) and the angle formed by \( 49^\circ \) and \( 3x^\circ \) are vertical angles? Wait, no, let's re-examine.
Wait, actually, the angle \( (7x - 23)^\circ \) and the angle adjacent to \( 49^\circ \) and \( 3x^\circ \) are vertical angles. Wait, maybe a better approach: the sum of angles around a point is \( 360^\circ \), but maybe we can use the fact that \( (7x - 23)^\circ \) and \( (3x + 49)^\circ \) are equal? Wait, no, let's check the linear pair.
Wait, actually, the angle \( (7x - 23)^\circ \) and the angle formed by \( 49^\circ \) and \( 3x^\circ \) are supplementary? Wait, no, let's look at the straight line. The angle \( (7x - 23)^\circ \) and the angle below it (formed by \( 49^\circ \) and \( 3x^\circ \)) are supplementary. Wait, actually, the correct approach is:
The angle \( (7x - 23)^\circ \) and the angle \( (3x + 49)^\circ \) are vertical angles? No, wait, let's see: when two lines intersect, vertical angles are equal. Wait, maybe the angle \( (7x - 23)^\circ \) is equal to \( (3x + 49)^\circ \)? Wait, no, let's check the sum.
Wait, actually, the sum of \( 49^\circ \), \( 3x^\circ \), and \( (7x - 23)^\circ \) is \( 180^\circ \) because they form a straight line. So:
\[
49 + 3x + (7x - 23) = 180
\]
Simplify the left side:
\[
49 - 23 + 3x + 7x = 180
\]
\[
26 + 10x = 180
\]
Subtract 26 from both sides:
\[
10x = 180 - 26
\]
\[
10x = 154
\]
Wait, that gives \( x = 15.4 \), which doesn't seem right. Maybe I made a mistake. Wait, maybe the angle \( (7x - 23)^\circ \) is equal to \( (3x + 49)^\circ \) because they are vertical angles. Let's try that:
\[
7x - 23 = 3x + 49
\]
Subtract \( 3x \) from both sides:
\[
4x - 23 = 49
\]
Add 23 to both sides:
\[
4x = 72
\]
Divide by 4:
\[
x = 18
\]
Ah, that makes sense. So \( x = 18 \).
Step 2: Solve for \( y \)
Now that we know \( x = 18 \), we can find \( 3x \):
\[
3x = 3 \times 18 = 54^\circ
\]
Now, the angle \( (11y - 1)^\circ \) is equal to \( 54^\circ \) because they are corresponding angles (since lines \( l \) and \( m \) are parallel? Wait, the diagram shows lines \( l \) and \( m \) with arrows, so they are parallel. So the angle \( (11y - 1)^\circ \) is equal to \( 3x^\circ \) (which is \( 54^\circ \)) because they are corresponding angles.
So:
\[
11y - 1 = 54
\]
Add 1 to both sides:
\[
11y = 55
\]
Divide by 11:
\[
y = 5
\]
Final Answers
For \( x \): \( \boxed{18} \)
For \( y \): \( \boxed{5} \)
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To solve for \( x \) and \( y \), we analyze the angles formed by intersecting lines.
Step 1: Solve for \( x \)
The angles \( 49^\circ \), \( (3x)^\circ \), and \( (7x - 23)^\circ \) are related such that the sum of angles on a straight line is \( 180^\circ \). However, we can also use the property of vertical angles or supplementary angles. Notice that \( (7x - 23)^\circ \) and \( (3x + 49)^\circ \) are supplementary (they form a linear pair). Wait, actually, looking at the diagram, the angle \( (7x - 23)^\circ \) and the angle formed by \( 49^\circ \) and \( 3x^\circ \) are vertical angles? Wait, no, let's re-examine.
Wait, actually, the angle \( (7x - 23)^\circ \) and the angle adjacent to \( 49^\circ \) and \( 3x^\circ \) are vertical angles. Wait, maybe a better approach: the sum of angles around a point is \( 360^\circ \), but maybe we can use the fact that \( (7x - 23)^\circ \) and \( (3x + 49)^\circ \) are equal? Wait, no, let's check the linear pair.
Wait, actually, the angle \( (7x - 23)^\circ \) and the angle formed by \( 49^\circ \) and \( 3x^\circ \) are supplementary? Wait, no, let's look at the straight line. The angle \( (7x - 23)^\circ \) and the angle below it (formed by \( 49^\circ \) and \( 3x^\circ \)) are supplementary. Wait, actually, the correct approach is:
The angle \( (7x - 23)^\circ \) and the angle \( (3x + 49)^\circ \) are vertical angles? No, wait, let's see: when two lines intersect, vertical angles are equal. Wait, maybe the angle \( (7x - 23)^\circ \) is equal to \( (3x + 49)^\circ \)? Wait, no, let's check the sum.
Wait, actually, the sum of \( 49^\circ \), \( 3x^\circ \), and \( (7x - 23)^\circ \) is \( 180^\circ \) because they form a straight line. So:
\[
49 + 3x + (7x - 23) = 180
\]
Simplify the left side:
\[
49 - 23 + 3x + 7x = 180
\]
\[
26 + 10x = 180
\]
Subtract 26 from both sides:
\[
10x = 180 - 26
\]
\[
10x = 154
\]
Wait, that gives \( x = 15.4 \), which doesn't seem right. Maybe I made a mistake. Wait, maybe the angle \( (7x - 23)^\circ \) is equal to \( (3x + 49)^\circ \) because they are vertical angles. Let's try that:
\[
7x - 23 = 3x + 49
\]
Subtract \( 3x \) from both sides:
\[
4x - 23 = 49
\]
Add 23 to both sides:
\[
4x = 72
\]
Divide by 4:
\[
x = 18
\]
Ah, that makes sense. So \( x = 18 \).
Step 2: Solve for \( y \)
Now that we know \( x = 18 \), we can find \( 3x \):
\[
3x = 3 \times 18 = 54^\circ
\]
Now, the angle \( (11y - 1)^\circ \) is equal to \( 54^\circ \) because they are corresponding angles (since lines \( l \) and \( m \) are parallel? Wait, the diagram shows lines \( l \) and \( m \) with arrows, so they are parallel. So the angle \( (11y - 1)^\circ \) is equal to \( 3x^\circ \) (which is \( 54^\circ \)) because they are corresponding angles.
So:
\[
11y - 1 = 54
\]
Add 1 to both sides:
\[
11y = 55
\]
Divide by 11:
\[
y = 5
\]
Final Answers
For \( x \): \( \boxed{18} \)
For \( y \): \( \boxed{5} \)