QUESTION IMAGE
Question
- find the value of x.
(6x + 7)° (8x - 17)°
- find the value of x.
(11x - 15)° (5x - 13)°
- if $overline{bd}perpoverline{ac}$, $mangle dbe=(2x - 1)°$, and $mangle cbe=(5x - 42)°$, find the value of x.
- find the value of x if $overline{qs}$ bisects $angle pqr$ and $mangle pqr = 82°$.
(10x + 1)°
- find the values of x and y.
(18y + 5)° (10x - 61)° (x + 10)°
- find the values of x and y.
(2y + 5)° (5x - 17)° (3x - 11)°
- if $overline{np}$ bisects $angle mnq$, $mangle mnq=(8x + 12)°$, $mangle pnq = 78°$, and $mangle rnm=(3y - 9)°$, find the values of x and y.
11.
Step1: Set up equation using vertical - angle property
Vertical angles are equal. So, \(6x + 7=8x - 17\).
Step2: Isolate \(x\) terms
Subtract \(6x\) from both sides: \(7 = 8x-6x - 17\), which simplifies to \(7 = 2x-17\).
Step3: Solve for \(x\)
Add 17 to both sides: \(7 + 17=2x\), so \(24 = 2x\). Then divide by 2: \(x = 12\).
Step1: Set up equation using angle - addition property
The sum of the two angles is \(11x-15=(5x - 13)\). This is incorrect. Assuming they are supplementary (if they form a straight - line), \((11x-15)+(5x - 13)=180\).
Step2: Combine like terms
\(11x+5x-15 - 13=180\), so \(16x-28 = 180\).
Step3: Isolate \(x\) term
Add 28 to both sides: \(16x=180 + 28=208\).
Step4: Solve for \(x\)
Divide both sides by 16: \(x=\frac{208}{16}=13\).
Step1: Use perpendicular - angle property
Since \(\overline{BD}\perp\overline{AC}\), \(\angle DBE+\angle CBE = 90^{\circ}\). So, \((2x - 1)+(5x - 42)=90\).
Step2: Combine like terms
\(2x+5x-1 - 42=90\), which gives \(7x-43 = 90\).
Step3: Isolate \(x\) term
Add 43 to both sides: \(7x=90 + 43=133\).
Step4: Solve for \(x\)
Divide both sides by 7: \(x = 19\).
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\(x = 12\)