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Question
(\frac{1}{6}(b + 12) = -4)
Step1: Multiply both sides by 6
To eliminate the fraction, we multiply both sides of the equation \(\frac{1}{6}(b + 12)=-4\) by 6. This gives us \(6\times\frac{1}{6}(b + 12)=6\times(-4)\). Simplifying the left side, the 6 and \(\frac{1}{6}\) cancel out, so we have \(b + 12=-24\).
Step2: Subtract 12 from both sides
Now, to solve for \(b\), we subtract 12 from both sides of the equation \(b + 12=-24\). So, \(b+12 - 12=-24 - 12\). Simplifying both sides, we get \(b=-36\).
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\(b = - 36\)