QUESTION IMAGE
Question
- $x^{2}+3x - 10$ $x^{2}+x - 6$
- $\frac{1}{x - 4}-\frac{1}{x}$
Step1: Find a common denominator
The common denominator of \(x - 4\) and \(x\) is \(x(x - 4)\).
Step2: Rewrite the fractions with the common denominator
\(\frac{1}{x - 4}-\frac{1}{x}=\frac{x}{x(x - 4)}-\frac{x - 4}{x(x - 4)}\)
Step3: Subtract the numerators
\(\frac{x-(x - 4)}{x(x - 4)}=\frac{x - x+4}{x(x - 4)}=\frac{4}{x(x - 4)}\)
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\(\frac{4}{x(x - 4)}\)