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Question
- please solve the equation below, showing your
$8(x + 8) - 6 \leq 98$
Step1: Expand the left side
$8(x+8)-6 = 8x + 64 - 6 = 8x + 58$
Step2: Isolate the term with x
$8x + 58 \leq 98$
$8x \leq 98 - 58$
$8x \leq 40$
Step3: Solve for x
$x \leq \frac{40}{8}$
$x \leq 5$
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$x \leq 5$