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Question
q.13 solve a right triangle gpr
solve the right triangle.
write your answers as integers or as decimals rounded to the nearest tenth.
$rs = $
$rt = $
$m\angle s = \square ^\circ$
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work it out
Step1: Find $m\angle S$
Sum of angles in $\triangle=180^\circ$
$m\angle S = 180^\circ - 90^\circ - 49^\circ = 41^\circ$
Step2: Calculate $RS$ (opposite $\angle T$)
Use sine function: $\sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}}$
$\sin(49^\circ)=\frac{RS}{4} \implies RS = 4\times\sin(49^\circ) \approx 4\times0.7547 \approx 3.0$
Step3: Calculate $RT$ (adjacent to $\angle T$)
Use cosine function: $\cos(\theta)=\frac{\text{adjacent}}{\text{hypotenuse}}$
$\cos(49^\circ)=\frac{RT}{4} \implies RT = 4\times\cos(49^\circ) \approx 4\times0.6561 \approx 2.6$
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$RS \approx 3.0$, $RT \approx 2.6$, $m\angle S = 41^\circ$