Question

1. 130 - 15x = 10
2. 63 - 5x = 28

Explanation:

Solving \( 130 - 15x = 10 \)

Step1: Subtract 130 from both sides

To isolate the term with \( x \), we subtract 130 from both sides of the equation \( 130 - 15x = 10 \).
\( 130 - 15x - 130 = 10 - 130 \)
Simplifying both sides, we get:
\( -15x = -120 \)

Step2: Divide both sides by -15

To solve for \( x \), we divide both sides of the equation \( -15x = -120 \) by -15.
\( \frac{-15x}{-15} = \frac{-120}{-15} \)
Simplifying both sides, we find:
\( x = 8 \)

Solving \( 63 - 5x = 28 \)

Step1: Subtract 63 from both sides

To isolate the term with \( x \), we subtract 63 from both sides of the equation \( 63 - 5x = 28 \).
\( 63 - 5x - 63 = 28 - 63 \)
Simplifying both sides, we get:
\( -5x = -35 \)

Step2: Divide both sides by -5

To solve for \( x \), we divide both sides of the equation \( -5x = -35 \) by -5.
\( \frac{-5x}{-5} = \frac{-35}{-5} \)
Simplifying both sides, we find:
\( x = 7 \)

Answer:

s:
For \( 130 - 15x = 10 \), \( x = \boldsymbol{8} \)
For \( 63 - 5x = 28 \), \( x = \boldsymbol{7} \)