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Question
- on a blueprint of a new house, a particular room has length 11 cm. the actual room has length 6.6 m and width 4.8 m. what is the width of the room on the blueprint? show how you found out.
Step1: Set up the proportion
Let the width on the blueprint be $x$ cm. First, convert the actual - length and actual - width to the same unit (cm). Since $1m = 100cm$, the actual length is $6.6m=6.6\times100 = 660$ cm and the actual width is $4.8m = 4.8\times100=480$ cm. The ratio of the length on the blueprint to the actual length is equal to the ratio of the width on the blueprint to the actual width. So we have the proportion $\frac{11}{660}=\frac{x}{480}$.
Step2: Cross - multiply
Cross - multiplying the proportion gives us $660x=11\times480$.
Step3: Solve for $x$
First, calculate $11\times480 = 5280$. Then, $x=\frac{5280}{660}$. Simplifying $\frac{5280}{660}$, we get $x = 8$ cm.
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8 cm