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q. 15. find gh given g(-6, -5) and h(2, 0). leave as a simplified radic…

Question

q. 15. find gh given g(-6, -5) and h(2, 0). leave as a simplified radical.

gh =

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Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $G(-6,-5)$ means $x_1=-6,y_1 = - 5$ and $H(2,0)$ means $x_2 = 2,y_2=0$.

Step2: Substitute values into formula

$GH=\sqrt{(2-(-6))^2+(0 - (-5))^2}=\sqrt{(2 + 6)^2+(0 + 5)^2}=\sqrt{8^2+5^2}$.

Step3: Calculate squares and sum

$\sqrt{8^2+5^2}=\sqrt{64 + 25}=\sqrt{89}$.

Answer:

$\sqrt{89}$