QUESTION IMAGE
Question
- find the values of x and y.
Step1: Set up equation for vertical - angles
Vertical - angles are equal. So, \(10x - 53=2x + 5\).
Step2: Solve for \(x\)
Subtract \(2x\) from both sides: \(10x-2x - 53=2x-2x + 5\), which simplifies to \(8x-53 = 5\). Then add 53 to both sides: \(8x-53 + 53=5 + 53\), giving \(8x=58\). Divide both sides by 8: \(x=\frac{58}{8}=\frac{29}{4}=7.25\).
Step3: Set up equation for linear - pair
The angles \((10x - 53)\) and \((18y + 11)\) form a linear - pair, so \((10x - 53)+(18y + 11)=180\). Substitute \(x = 7.25\) into the equation: \((10\times7.25-53)+(18y + 11)=180\). First, calculate \(10\times7.25-53=72.5 - 53 = 19.5\). The equation becomes \(19.5+18y + 11=180\). Combine like - terms: \(18y+30.5 = 180\). Subtract 30.5 from both sides: \(18y=180 - 30.5=149.5\). Divide both sides by 18: \(y=\frac{149.5}{18}=\frac{299}{36}\approx8.31\).
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\(x = 7.25\), \(y=\frac{299}{36}\approx8.31\)