Question

1. reflection across x = 1

Explanation:

Step1: Identify original coordinates

Original points: $V(0,2)$, $W(1,4)$, $X(5,2)$

Step2: Use reflection formula for $x=1$

For a point $(x,y)$, reflection over $x=a$ is $(2a-x,y)$. Here $a=1$, so formula is $(2-x,y)$.

• For $V(0,2)$: $x'=2-0=2$, $y'=2$ → $V'(2,2)$
• For $W(1,4)$: $x'=2-1=1$, $y'=4$ → $W'(1,4)$
• For $X(5,2)$: $x'=2-5=-3$, $y'=2$ → $X'(-3,2)$

Answer:

The coordinates of the reflected triangle are $V'(2,2)$, $W'(1,4)$, $X'(-3,2)$