Question

1. what is the range of the function $f(x) = x^2 + 3$ if the domain is {0,1,4,9}?

Explanation:

Step1: Substitute \( x = 0 \)

\( f(0)=0^{2}+3 = 3 \)

Step2: Substitute \( x = 1 \)

\( f(1)=1^{2}+3 = 4 \)

Step3: Substitute \( x = 4 \)

\( f(4)=4^{2}+3 = 16 + 3=19 \)

Step4: Substitute \( x = 9 \)

\( f(9)=9^{2}+3 = 81+3 = 84 \)

Answer:

The range of the function is \(\{3, 4, 19, 84\}\)