Question

for 5 - 16, find each sum. use a tool as needed.

1. $\frac{3}{12} + \frac{4}{12}$
2. $\frac{4}{10} + \frac{1}{10}$
3. $\frac{2}{12} + \frac{4}{12}$
4. $\frac{1}{6} + \frac{2}{6} + \frac{3}{6}$
5. $\frac{1}{4} + \frac{2}{4}$
6. $\frac{1}{3} + \frac{1}{3}$
7. $\frac{5}{8} + \frac{1}{8}$
8. $\frac{1}{4} + \frac{3}{4}$
9. $\frac{7}{12} + \frac{2}{12}$
10. $\frac{1}{4} + \frac{1}{4}$
11. $\frac{2}{5} + \frac{2}{5}$
12. $\frac{1}{10} + \frac{2}{10} + \frac{1}{10}$

topic 9 | lesson 9 - 1 335

Explanation:

Problem 5: $\boldsymbol{\frac{3}{12} + \frac{4}{12}}$

Step1: Add numerators (denominators same)

For fractions with the same denominator, we add the numerators and keep the denominator. So, $3 + 4 = 7$.

Step2: Write the result

The denominator remains 12. So the sum is $\frac{7}{12}$.

Step1: Add numerators (denominators same)

Add the numerators: $4 + 1 = 5$.

Step2: Simplify (optional)

The fraction is $\frac{5}{10}$, which simplifies to $\frac{1}{2}$ (dividing numerator and denominator by 5).

Step1: Add numerators (denominators same)

$2 + 4 = 6$.

Step2: Simplify

$\frac{6}{12}$ simplifies to $\frac{1}{2}$ (dividing by 6).

Answer:

$\frac{7}{12}$

Problem 6: $\boldsymbol{\frac{4}{10} + \frac{1}{10}}$