Question

18
factor by gcf
$18xy^{2}-24xy$
$3xy(6y-8)$
$9xy(2x-3)$
$8xy(2y-3)$
$6xy(3y-4)$

Explanation:

Step1: Find GCF of coefficients

GCF of 18 and 24 is 6.

Step2: Find GCF of variables

GCF of $xy^2$ and $xy$ is $xy$.

Step3: Combine GCFs

Overall GCF is $6xy$.

Step4: Factor out GCF

Divide each term by $6xy$:
$\frac{18xy^2}{6xy} - \frac{24xy}{6xy} = 3y - 4$
So factored form: $6xy(3y-4)$

Answer:

6xy(3y-4)