Question

1. you use a tape measure to measure the dimensions of a canvas, as shown. estimate the area of the canvas. 50.8 cm 40.6 cm

Explanation:

Answer:

To estimate the area of the canvas (which appears to be a rectangle), we use the formula for the area of a rectangle, \( A = \text{length} \times \text{width} \).

Given:

• Length (\( l \)) = \( 50.8 \, \text{cm} \)
• Width (\( w \)) = \( 40.6 \, \text{cm} \)

\[
A = 50.8 \times 40.6
\]

First, approximate the values:

• \( 50.8 \approx 50 \) or \( 51 \), but to be closer, we can multiply directly or round to simpler numbers. However, for estimation, we can use \( 50 \times 40 = 2000 \), but a better estimate is:

\[
50.8 \times 40.6 \approx 50 \times 40 + 50 \times 0.6 + 0.8 \times 40 + 0.8 \times 0.6 = 2000 + 30 + 32 + 0.48 = 2062.48
\]

Or, more simply, \( 50.8 \times 40.6 \approx 50 \times 40.6 + 0.8 \times 40.6 = 2030 + 32.48 = 2062.48 \, \text{cm}^2 \).

A reasonable estimate (rounding to whole numbers) is approximately \( 2062 \, \text{cm}^2 \) (or \( 2060 \, \text{cm}^2 \) for a simpler estimate).

(If we use exact multiplication: \( 50.8 \times 40.6 = 2062.48 \, \text{cm}^2 \), so the area is approximately \( 2062 \, \text{cm}^2 \) or \( 2060 \, \text{cm}^2 \) when estimated.)