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2025/2026 - ia2 : period 6/7
homework: 4.1 intro to quad
question 7, 4.1.32 part 2 of 2
hw score: 27.78%, 5 of 18 points
points: 0 of 1
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sketch the graph of the quadratic function and the axis of symmetry.
$f(x) = -3(x + 6)^2 + 4$
use the graphing tool to graph the function as a solid curve and the axis of symmetry as a dashed line.
the axis of symmetry is
(graph with a parabola and grid visible)

Explanation:

Step1: Identify vertex form

Quadratic vertex form: $f(x)=a(x-h)^2+k$, where $(h,k)$ is vertex, axis of symmetry is $x=h$.
Given $f(x)=-3(x+6)^2+4 = -3(x-(-6))^2+4$

Step2: Find axis of symmetry

Match to vertex form: $h=-6$. Axis of symmetry is $x=h$.
Expression: $x=-6$

Answer:

$x=-6$

(For graphing: The parabola opens downward (since $a=-3<0$) with vertex at $(-6,4)$, and the dashed axis of symmetry is the vertical line $x=-6$.)