Question

1. jackson and cheyenne are getting married and need to order cake for their guests. they have invited 225 people, and each cake can serve 48 people. how many need?

4 cakes
4.5 cakes
5 cakes
8 cakes

1. mrs. wheeler is responsible for planning the junior prom for the students. the students voted and decided to have a paris theme for the dance. mrs. wheeler bought the decorations for the ballroom. she bought a photo booth decorated as the eiffel tower for $125.00, 3 balloon arches for $49.99 each, 25 paper lanterns for $2.50 each, and 10 strings of hanging lights for $3.99 each. what is the total cost of the decorations mrs. wheeler bought for the ballroom?

$256.75
$377.37
$181.48
$149.97

Explanation:

Question 26

Step1: Divide total guests by per - cake servings

To find the number of cakes needed, we divide the total number of guests (225) by the number of people each cake can serve (48). So we calculate $\frac{225}{48}=4.6875$.

Step2: Apply the ceiling function (since we can't order a fraction of a cake)

Since we can't order a part of a cake and we need to make sure all guests are served, we use the ceiling function. The ceiling of 4.6875 is 5, which means we need to order 5 cakes.

Step1: Calculate the cost of balloon arches

Mrs. Wheeler bought 3 balloon arches at $49.99 each. So the cost of balloon arches is $3\times49.99 = 149.97$.

Step2: Calculate the cost of paper lanterns

She bought 25 paper lanterns at $2.50 each. So the cost of paper lanterns is $25\times2.50=62.5$.

Step3: Calculate the cost of hanging lights

She bought 10 strings of hanging lights at $3.99 each. So the cost of hanging lights is $10\times3.99 = 39.9$.

Step4: Add the cost of all items

The cost of the photo booth is $125.00. Now we add up all the costs: $125+149.97 + 62.5+39.9$.
First, $125+149.97=274.97$. Then, $274.97+62.5 = 337.47$. Then, $337.47+39.9 = 377.37$.

Answer:

5 cakes

Question 27