Question

-2x - 5y = -5\
-3x - 10y = -20\
(\boxed{ }, \boxed{ })\
submit

Explanation:

Step1: Analyze the system of equations

We have the system:
\[

$$\begin{cases} -2x - 5y = -5 \\ -3x - 10y = -20 \end{cases}$$

\]
Let's use the elimination method. First, multiply the first equation by 2 to make the coefficients of \(y\) opposite:
\[
-4x - 10y = -10
\]

Step2: Subtract the second equation

Now subtract the second equation \(-3x - 10y = -20\) from the new first equation:
\[
(-4x - 10y) - (-3x - 10y) = -10 - (-20)
\]
Simplify the left side:
\[
-4x - 10y + 3x + 10y = -10 + 20
\]
\[
-x = 10
\]
So \(x = -10\)

Step3: Substitute \(x\) into the first equation

Substitute \(x = -10\) into \(-2x - 5y = -5\):
\[
-2(-10) - 5y = -5
\]
\[
20 - 5y = -5
\]
Subtract 20 from both sides:
\[
-5y = -5 - 20
\]
\[
-5y = -25
\]
Divide both sides by -5:
\[
y = 5
\]

Answer:

The solution to the system of equations is \(x = -10\) and \(y = 5\). If we assume the boxes are for the solution of the system (maybe in the form of \((x,y)\)), then the answer is \((-10, 5)\)