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f(x)=\\begin{cases}-2x + 1, & x < 1 \\\\ \\dfrac{2}{3}x - 3, & x \\geq …

Question

f(x)=\

$$\begin{cases}-2x + 1, & x < 1 \\\\ \\dfrac{2}{3}x - 3, & x \\geq 1\\end{cases}$$

evaluate f(6)
type answer here.

Explanation:

Step1: Determine the applicable function

Since \( 6 \geq 1 \), we use the function \( f(x)=\frac{2}{3}x - 3 \).

Step2: Substitute \( x = 6 \) into the function

Substitute \( x = 6 \) into \( \frac{2}{3}x - 3 \):
\( \frac{2}{3} \times 6 - 3 \)
First, calculate \( \frac{2}{3} \times 6 = 4 \).
Then, \( 4 - 3 = 1 \).

Answer:

\( 1 \)