Question

n(x) = \frac{1}{4}x^2 - 2x + 4
what is the value of n(m(4))?
\circ -4
\circ -2
\circ 0

Explanation:

Step1: Find m(4) from the graph

Locate $x=4$ on the x-axis, the corresponding $m(4)=4$.

Step2: Substitute into n(x)

Plug $m(4)=4$ into $n(x)=\frac{1}{4}x^2 - 2x + 4$.
$\displaystyle n(4)=\frac{1}{4}(4)^2 - 2(4) + 4$

Step3: Calculate the value

First compute each term: $\frac{1}{4}(16)=4$, $2(4)=8$. Then combine: $4 - 8 + 4 = 0$.

Answer:

0