Question

m(-3, -1) is the midpoint of segment fg. point g is at (-8, 6). what are the coordinates of point f? (find the missing endpoint.)

Explanation:

Step1: Recall mid - point formula

The mid - point formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $M=(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$. Let the coordinates of point $F$ be $(x,y)$ and point $G(-8,6)$ and mid - point $M(-3,-1)$.

Step2: Find the x - coordinate of point F

We know that $\frac{x+( - 8)}{2}=-3$. Multiply both sides by 2: $x - 8=-6$. Then add 8 to both sides: $x=-6 + 8=2$.

Step3: Find the y - coordinate of point F

We know that $\frac{y + 6}{2}=-1$. Multiply both sides by 2: $y+6=-2$. Then subtract 6 from both sides: $y=-2-6=-8$.

Answer:

$(2,-8)$