Question

1. in snapdragons, flower color is controlled by incomplete dominance. the two alleles are red (r) and white (r). the heterozygous genotype is expressed as pink.a. what is the phenotype of a plant with the genotype rr?b. what is the phenotype of a plant with the genotype rr?c. what is the phenotype of a plant with the genotype rr?cross a pink-flowered plant with a white-flowered plant.d.e. what is the probability of producing a pink-flowered plant (percentage)?34. human blood types are determined by genes that follow the codominance pattern of inheritance. there are two dominant alleles ($i^a$ and $i^b$) and one recessive allele (i).write the genotype for each person based on their description:a. homozygous for the \b\ alleleb. heterozygous for the \a\ allelec. type od. type \a\ and had a type \o\ parente. type \ab\if drake is homozygous for the type b allele and nicki is type \o,\ what are all the possible blood types of their offspring?35. hemophilia is a recessive, x-linked genetic disorder. affected individuals blood does not clot properly. cross a male with hemophilia with a female who is neither affected nor is a carrier of the disease.what is the likelihood (in percent) that they will have a child with hemophilia?

Explanation:

Step1: Solve 33 (incomplete dominance)

33a: Identify RR phenotype

RR is homozygous red, so phenotype = Red

33b: Identify Rr phenotype

Rr is heterozygous, expressed as Pink

33c: Identify rr phenotype

rr is homozygous white, so phenotype = White

33d: Set up Punnett square

Pink plant (Rr) × White plant (rr). Gametes: Rr gives $R, r$; rr gives $r, r$.
Punnett square:

	R	r
r	Rr	rr

33e: Calculate pink probability

2 out of 4 offspring are Rr (pink). Percentage = $\frac{2}{4} \times 100\% = 50\%$

Step2: Solve 34 (codominant blood types)

34a: Homozygous B genotype

Homozygous for $I^B$ = $I^BI^B$

34b: Heterozygous A genotype

Heterozygous for $I^A$ = $I^Ai$

34c: Type O genotype

Type O is recessive, genotype = $ii$

34d: Type A with O parent

O parent gives $i$, so Type A must be $I^Ai$

34e: Type AB genotype

AB has both dominant alleles = $I^AI^B$

34f: Cross Drake ($I^BI^B$) × Nicki ($ii$)

Gametes: Drake gives $I^B$; Nicki gives $i$. All offspring = $I^Bi$, so blood type = Type B

Step3: Solve 35 (X-linked hemophilia)

35a: Define parental genotypes

Affected male: $X^hY$; Unaffected non-carrier female: $X^HX^H$

35b: Set up Punnett square

Gametes: Male gives $X^h, Y$; Female gives $X^H, X^H$
Punnett square:

	$X^h$	$Y$
$X^H$	$X^HX^h$	$X^HY$

35c: Calculate hemophilia likelihood

No offspring has $X^hX^h$ (affected female) or $X^hY$ (affected male). Percentage = $0\%$

Answer:

Question 33

a. Red
b. Pink
c. White
d. Punnett square yields 2 Rr (pink) and 2 rr (white) offspring
e. 50%

Question 34

a. $I^BI^B$
b. $I^Ai$
c. $ii$
d. $I^Ai$
e. $I^AI^B$
f. Type B (all offspring have genotype $I^Bi$)

Question 35

0%