Question

a^{2}+b^{2}=c^{2}
a = 9 b = 40
c = 65
c = 25
c = 41
c = 5

Explanation:

Step1: Substitute values of a and b

Given $a = 9$ and $b = 40$, substitute into $a^{2}+b^{2}=c^{2}$. So we have $9^{2}+40^{2}=c^{2}$.

Step2: Calculate squares

$9^{2}=81$ and $40^{2}=1600$. Then $81 + 1600=c^{2}$, so $c^{2}=1681$.

Step3: Find square - root of $c^{2}$

Since $c>0$ (in the context of length etc.), $c=\sqrt{1681}=41$.

Answer:

C. $c = 41$