Question

$v = b^{2}/4 (\frac{h}{2})LXB0a=88×17424=17512LXB1sa=17424×123232LXB2=sqrt{17424}-sqrt{17424}$d. 4680.8. the base of a right pyramid is a square with side length of 40 cm. if the volume of the pyramid is $8000\\ \text{cm}^3$, what is the height of the pyramid?

Explanation:

Step1: Recall pyramid volume formula

The volume of a right pyramid is $V = \frac{1}{3}Bh$, where $B$ is the base area, $h$ is height.

Step2: Calculate base area

Base is a square with side $40$ cm, so $B = 40 \times 40 = 1600$ $\text{cm}^2$.

Step3: Rearrange formula to solve for $h$

Rearrange $V = \frac{1}{3}Bh$ to $h = \frac{3V}{B}$.

Step4: Substitute values and compute

Substitute $V=8000$ $\text{cm}^3$, $B=1600$ $\text{cm}^2$:
$h = \frac{3 \times 8000}{1600} = \frac{24000}{1600} = 15$

Answer:

15 cm