Question

5-2 hw - solving one-step equations with multiplication and division tions : solve each equation using inverse operations, then check your solution. must show all the steps as discussed in class in order to receive full credit for this assignment. solve each equation: 1. 16b = 32 4. \\(\frac{h}{3} = -7\\) 2. -3n = -45 5. \\(\frac{a}{13} = 0\\) 3. -99 = -99y 6. -12k = 60

Explanation:

1. Solve $16b=32$

Step1: Divide both sides by 16

$\frac{16b}{16}=\frac{32}{16}$

Step2: Simplify to find $b$

$b=2$

Step3: Check solution

$16(2)=32$, $32=32$ (valid)

2. Solve $-3n=-45$

Step1: Divide both sides by $-3$

$\frac{-3n}{-3}=\frac{-45}{-3}$

Step2: Simplify to find $n$

$n=15$

Step3: Check solution

$-3(15)=-45$, $-45=-45$ (valid)

3. Solve $-99=-99y$

Step1: Divide both sides by $-99$

$\frac{-99}{-99}=\frac{-99y}{-99}$

Step2: Simplify to find $y$

$y=1$

Step3: Check solution

$-99=-99(1)$, $-99=-99$ (valid)

4. Solve $\frac{h}{3}=-7$

Step1: Multiply both sides by 3

$3\times\frac{h}{3}=3\times(-7)$

Step2: Simplify to find $h$

$h=-21$

Step3: Check solution

$\frac{-21}{3}=-7$, $-7=-7$ (valid)

5. Solve $\frac{a}{13}=0$

Step1: Multiply both sides by 13

$13\times\frac{a}{13}=13\times0$

Step2: Simplify to find $a$

$a=0$

Step3: Check solution

$\frac{0}{13}=0$, $0=0$ (valid)

6. Solve $-12k=60$

Step1: Divide both sides by $-12$

$\frac{-12k}{-12}=\frac{60}{-12}$

Step2: Simplify to find $k$

$k=-5$

Step3: Check solution

$-12(-5)=60$, $60=60$ (valid)

Answer:

1. $b=2$
2. $n=15$
3. $y=1$
4. $h=-21$
5. $a=0$
6. $k=-5$