Question

(5r² + 3r + 3) - (3r - r² - 4)

Explanation:

Step1: Remove parentheses

To remove the parentheses, we distribute the negative sign to the terms inside the second parentheses:
$$(5r^2 + 3r + 3) - (3r - r^2 - 4) = 5r^2 + 3r + 3 - 3r + r^2 + 4$$

Step2: Combine like terms

• For the \(r^2\) terms: \(5r^2 + r^2 = 6r^2\)
• For the \(r\) terms: \(3r - 3r = 0\)
• For the constant terms: \(3 + 4 = 7\)

Putting it all together, we get \(6r^2 + 0 + 7 = 6r^2 + 7\)

Answer:

\(6r^2 + 7\)