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5th period 2 - 3: mathxl for school: practice & problem - solving copy …

Question

5th period 2 - 3: mathxl for school: practice & problem - solving copy 1 due sep 24 - 11:45 pm part 1 of 2 for the figure shown, find m∠1 and m∠2. (the figure is not drawn to scale.) m∠1 = □°

Explanation:

Step1: Use exterior - angle property for ∠1

The exterior - angle of a triangle is equal to the sum of the two non - adjacent interior angles. For the triangle with angles 32° and 34°, ∠1 is an exterior angle. So, $m\angle1=32^{\circ}+34^{\circ}$.

Step2: Calculate the value of ∠1

$m\angle1 = 66^{\circ}$

Step3: Use linear - pair property for ∠2

∠2 and the 93° angle form a linear pair. A linear pair of angles is supplementary, meaning their sum is 180°. So, $m\angle2=180^{\circ}-93^{\circ}$.

Step4: Calculate the value of ∠2

$m\angle2 = 87^{\circ}$

Answer:

$m\angle1 = 66^{\circ}$, $m\angle2 = 87^{\circ}$