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Question
67.) triangle with base - related side 3 m and height 1.9 m 68.) triangle with base 6 ft and height 4 ft
Assuming the problem is to find the area of the triangles:
For Problem 67 (Triangle with base 3 m and height 1.9 m)
Step1: Recall the formula for the area of a triangle
The formula for the area of a triangle is $A = \frac{1}{2} \times \text{base} \times \text{height}$.
Step2: Identify the base and height
Here, the base is $3$ m and the height is $1.9$ m.
Step3: Substitute the values into the formula
$A = \frac{1}{2} \times 3 \times 1.9$
Step4: Calculate the result
First, calculate $3 \times 1.9 = 5.7$. Then, $\frac{1}{2} \times 5.7 = 2.85$.
Step1: Recall the formula for the area of a triangle
The formula for the area of a triangle is $A = \frac{1}{2} \times \text{base} \times \text{height}$.
Step2: Identify the base and height
Here, the base is $6$ ft and the height is $4$ ft.
Step3: Substitute the values into the formula
$A = \frac{1}{2} \times 6 \times 4$
Step4: Calculate the result
First, calculate $6 \times 4 = 24$. Then, $\frac{1}{2} \times 24 = 12$.
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The area of the triangle in problem 67 is $2.85$ square meters.