Question

90° clockwise rotation
rule (x, y): (□, □)
e(□, □)
f(□, □)
g(□, □)
h(□, □)

Explanation:

Step1: Recall 90° clockwise rotation rule

The rule for a \( 90^\circ \) clockwise rotation about the origin is \((x, y) \to (y, -x)\).

Step2: Find coordinates of original points

• \( E(-4, 1) \)
• \( F(0, 1) \)
• \( G(1, -1) \)
• \( H(-5, -1) \)

Step3: Apply rotation rule to \( E \)

For \( E(-4, 1) \): \( x=-4, y = 1 \). New coordinates \( (y, -x)=(1, -(-4))=(1, 4) \), so \( E'(1, 4) \).

Step4: Apply rotation rule to \( F \)

For \( F(0, 1) \): \( x = 0, y=1 \). New coordinates \( (y, -x)=(1, -0)=(1, 0) \), so \( F'(1, 0) \).

Step5: Apply rotation rule to \( G \)

For \( G(1, -1) \): \( x = 1, y=-1 \). New coordinates \( (y, -x)=(-1, -1) \), so \( G'(-1, -1) \).

Step6: Apply rotation rule to \( H \)

For \( H(-5, -1) \): \( x=-5, y = -1 \). New coordinates \( (y, -x)=(-1, -(-5))=(-1, 5) \), so \( H'(-1, 5) \).

Answer:

Rule \((x, y)\): \((y, -x)\)
\( E'(1, 4) \)
\( F'(1, 0) \)
\( G'(-1, -1) \)
\( H'(-1, 5) \)