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0 = \\sqrt3{924 + z} - 12

Question

0 = \sqrt3{924 + z} - 12

Explanation:

Step1: Isolate the cube root term

Add 12 to both sides of the equation \(0 = \sqrt[3]{924 + z} - 12\) to get \(\sqrt[3]{924 + z}=12\).

Step2: Eliminate the cube root

Cube both sides of the equation \(\sqrt[3]{924 + z}=12\). We know that \((\sqrt[3]{a})^3=a\), so \((\sqrt[3]{924 + z})^3 = 12^3\), which simplifies to \(924+z = 1728\).

Step3: Solve for z

Subtract 924 from both sides of the equation \(924+z = 1728\). So \(z=1728 - 924\).

Step4: Calculate the value of z

Calculate \(1728-924 = 804\).

Answer:

\(z = 804\)