Question

1.9cm
2.4cm
d

Explanation:

Step1: Apply Pythagorean theorem

For a right - triangle with legs \(a = 1.9\mathrm{cm}\) and \(b = 2.4\mathrm{cm}\), and hypotenuse \(d\), the Pythagorean theorem is \(d=\sqrt{a^{2}+b^{2}}\).

Step2: Calculate \(a^{2}\) and \(b^{2}\)

\(a^{2}=(1.9)^{2}=3.61\) and \(b^{2}=(2.4)^{2}=5.76\).

Step3: Calculate \(a^{2}+b^{2}\)

\(a^{2}+b^{2}=3.61 + 5.76=9.37\).

Step4: Calculate \(d\)

\(d=\sqrt{9.37}\approx3.06\mathrm{cm}\)

Answer:

\(d\approx3.06\mathrm{cm}\)