Question

add.
\\(\left(-8r^{2} + 7r - 2\
ight) + \left(r - 6\
ight)\\)

Explanation:

Step1: Remove parentheses

$-8r^2 + 7r - 2 + r - 6$

Step2: Combine like terms ($r$ terms)

$-8r^2 + (7r + r) - 2 - 6 = -8r^2 + 8r - 2 - 6$

Step3: Combine constant terms

$-8r^2 + 8r + (-2 - 6) = -8r^2 + 8r - 8$

Answer:

$-8r^2 + 8r - 8$