Question

after school, seki and fernando walk home. seki walks 5 blocks east and 10 blocks north. fernando walks 10 blocks east and 8 blocks south. on the graph, the school is located at the origin. determine the distance between sekis house (point s) and fernandos house (point f). enter the coordinates of the two given points and then calculate the distance between them. coordinates (x1, y1) of point s: (?,?) coordinates (x2, y2) of point f: (?,?) d = \sqrt{(x2 - x1)^2+(y2 - y1)^2} d = \sqrt{( )^2+( )^2} d =

Explanation:

Step1: Determine coordinates of point S

Seki walks 5 blocks east (positive x - direction) and 10 blocks north (positive y - direction). So the coordinates of point S are $(x_1,y_1)=(5,10)$.

Step2: Determine coordinates of point F

Fernando walks 10 blocks east (positive x - direction) and 8 blocks south (negative y - direction). So the coordinates of point F are $(x_2,y_2)=(10, - 8)$.

Step3: Calculate distance

Substitute the coordinates into the distance formula $d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.
$d=\sqrt{(10 - 5)^2+(-8 - 10)^2}=\sqrt{5^2+(-18)^2}=\sqrt{25 + 324}=\sqrt{349}\approx18.68$.

Answer:

Coordinates of point S: $(5,10)$
Coordinates of point F: $(10,-8)$
$d=\sqrt{(10 - 5)^2+(-8 - 10)^2}$
$d=\sqrt{349}\approx18.68$