Question

xᴮ = allele for unaffected vision
xᵇ = allele for color blindness

make a punnett square for a mother who is a carrier for color blindness and a father is color blind.

Explanation:

Step1: Identify parental genotypes

Mother (carrier): $X^BX^b$; Father (color blind): $X^bY$

Step2: Set up Punnett square axes

Mother's gametes: $X^B$, $X^b$ (top row); Father's gametes: $X^b$, $Y$ (left column)

Step3: Fill in Punnett square

Top-left (mother $X^B$ + father $X^b$): $X^BX^b$
Top-right (mother $X^b$ + father $X^b$): $X^bX^b$
Bottom-left (mother $X^B$ + father $Y$): $X^BY$
Bottom-right (mother $X^b$ + father $Y$): $X^bY$

Answer:

	$X^B$	$X^b$
$Y$	$X^BY$	$X^bY$

The genotypes of the offspring are: 1. $X^BX^b$ (carrier daughter), 2. $X^bX^b$ (color blind daughter), 3. $X^BY$ (unaffected son), 4. $X^bY$ (color blind son)