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Question
angle trigonometry given right triangle gyk, what is the value of tan(g)?
Step1: Recall tangent formula
$\tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}$ for an angle $\theta$ in a right - triangle.
For $\angle G = 60^{\circ}$ in right - triangle $GYK$, if we assume the side opposite to $\angle G$ has length $\sqrt{3}$ and the side adjacent to $\angle G$ has length $1$.
Step2: Calculate $\tan(G)$
$\tan(G)=\tan(60^{\circ})=\frac{\sqrt{3}}{1}=\sqrt{3}$
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$\sqrt{3}$