Question

applying trigonometric ratios to estimate side lengths
rounded to the nearest tenth, what is the length of ln
sin(20°) = \frac{ln}{8}
(8)sin(20°) = ln
= ln

Explanation:

Step1: Recall sine - value calculation

We know that $\sin(20^{\circ})\approx0.342$.

Step2: Calculate the length of LN

Since $LN = 8\times\sin(20^{\circ})$, substituting the value of $\sin(20^{\circ})$, we get $LN=8\times0.342 = 2.736$.

Step3: Round to the nearest tenth

Rounding $2.736$ to the nearest tenth gives $2.7$.

Answer:

$2.7$