Question

area of a trapezoid

1. a=
2. a=
3. a=
4. a=
5. a=
6. a=
7. a=
8. a=
9. a=

Explanation:

Step1: Recall trapezoid area formula

The area formula of a trapezoid is $A=\frac{(b_1 + b_2)h}{2}$, where $b_1$ and $b_2$ are the lengths of the parallel - sides and $h$ is the height.

Step2: Solve for problem (1)

Given $b_1 = 6$, $b_2=10$, $h = 11$. Substitute into the formula: $A=\frac{(6 + 10)\times11}{2}=\frac{16\times11}{2}=88$.

Step3: Solve for problem (2)

Given $b_1 = 3$, $b_2 = 5$, $h=2$. Substitute into the formula: $A=\frac{(3 + 5)\times2}{2}=8$.

Step4: Solve for problem (3)

Given $b_1 = 4$, $b_2 = 5$, $h = 8$. Substitute into the formula: $A=\frac{(4 + 5)\times8}{2}=\frac{9\times8}{2}=36$.

Step5: Solve for problem (4)

Given $b_1 = 4$, $b_2 = 7$, $h=2$. Substitute into the formula: $A=\frac{(4 + 7)\times2}{2}=11$.

Step6: Solve for problem (5)

Given $b_1 = 9$, $b_2 = 15$, $h = 6$. Substitute into the formula: $A=\frac{(9+15)\times6}{2}=\frac{24\times6}{2}=72$.

Step7: Solve for problem (6)

Given $b_1 = 8$, $b_2 = 9$, $h = 6$. Substitute into the formula: $A=\frac{(8 + 9)\times6}{2}=\frac{17\times6}{2}=51$.

Step8: Solve for problem (7)

Given $b_1 = 4$, $b_2 = 25$, $h = 9$. Substitute into the formula: $A=\frac{(4 + 25)\times9}{2}=\frac{29\times9}{2}=130.5$.

Step9: Solve for problem (8)

Given $b_1 = 6$, $b_2 = 6$, $h = 3$. Substitute into the formula: $A=\frac{(6 + 6)\times3}{2}=\frac{12\times3}{2}=18$.

Step10: Solve for problem (9)

Given $b_1 = 8$, $b_2 = 14$, $h = 8$. Substitute into the formula: $A=\frac{(8 + 14)\times8}{2}=\frac{22\times8}{2}=88$.

Answer:

1. $A = 88$
2. $A = 8$
3. $A = 36$
4. $A = 11$
5. $A = 72$
6. $A = 51$
7. $A = 130.5$
8. $A = 18$
9. $A = 88$