Question

attempt 1: 10 attempts remaining.
find the limit of the function at the given point:
\\(\lim_{x \to -11} (2x^2 + 5x - 27) =\\)

Explanation:

Step1: Substitute \( x = -11 \) into the function

For the function \( f(x) = 2x^2 + 5x - 27 \), we substitute \( x=-11 \) into it. So we calculate each term:

• First term: \( 2x^2 = 2\times(-11)^2 \). Since \( (-11)^2 = 121 \), then \( 2\times121 = 242 \).
• Second term: \( 5x = 5\times(-11)= -55 \).
• Third term: \( -27 \) remains as it is.

Step2: Combine the terms

Now we combine these three results: \( 242 + (-55) - 27 \). First, \( 242-55 = 187 \), then \( 187 - 27 = 160 \).

Answer:

\( 160 \)