Question

1. a baseball player has 12 more hits than doubles. if together the number of hits and doubles is 48, how many doubles does the player have?

Explanation:

Step1: Define variables

Let \( d \) be the number of doubles. Then the number of hits is \( d + 12 \).

Step2: Set up equation

The sum of hits and doubles is 48, so \( d+(d + 12)=48 \).

Step3: Simplify equation

Combine like terms: \( 2d+12 = 48 \).

Step4: Solve for \( d \)

Subtract 12 from both sides: \( 2d=48 - 12=36 \). Then divide by 2: \( d=\frac{36}{2}=18 \).

Answer:

18