QUESTION IMAGE
Question
calindo algebra 1b
name:
date:
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perfect squares & cubes
find the following square and cube roots.
- $sqrt{144}$ =
- $sqrt{16}$ =
- $sqrt{289}$ =
- $sqrt{\frac{4}{81}}$ =
- $sqrt{25}$ =
- $sqrt{400}$ =
- $sqrt3{27}$ =
- $sqrt3{-8}$ =
- $sqrt3{216}$ =
- $sqrt3{343}$ =
- $sqrt3{-1000}$ =
- $sqrt3{1}$ =
Step1: Find square root of 144
$\sqrt{144} = 12$
Step2: Find square root of 16
$\sqrt{16} = 4$
Step3: Find square root of 289
$\sqrt{289} = 17$
Step4: Find square root of $\frac{4}{81}$
$\sqrt{\frac{4}{81}} = \frac{\sqrt{4}}{\sqrt{81}} = \frac{2}{9}$
Step5: Find square root of 25
$\sqrt{25} = 5$
Step6: Find square root of 400
$\sqrt{400} = 20$
Step7: Find cube root of 27
$\sqrt[3]{27} = 3$
Step8: Find cube root of -8
$\sqrt[3]{-8} = -2$
Step9: Find cube root of 216
$\sqrt[3]{216} = 6$
Step10: Find cube root of 343
$\sqrt[3]{343} = 7$
Step11: Find cube root of -1000
$\sqrt[3]{-1000} = -10$
Step12: Find cube root of 1
$\sqrt[3]{1} = 1$
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- $12$
- $4$
- $17$
- $\frac{2}{9}$
- $5$
- $20$
- $3$
- $-2$
- $6$
- $7$
- $-10$
- $1$