Question

cameron, arthur, and jamie are playing soccer. their locations are recorded by a motion - tracking system. see examples 4 and 5. 22. how far apart are arthur and jamie? round to the nearest tenth of a meter.

Explanation:

Step1: Identify coordinates

Arthur's coordinates seem to be (20, 40) and Jamie's are (50, 30).

Step2: Use distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1 = 20,y_1 = 40,x_2 = 50,y_2 = 30$. So $d=\sqrt{(50 - 20)^2+(30 - 40)^2}=\sqrt{30^2+( - 10)^2}=\sqrt{900 + 100}=\sqrt{1000}$.

Step3: Calculate and round

$\sqrt{1000}\approx31.6$ (rounded to the nearest tenth).

Answer:

31.6