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challenge the vertices of pentagon vwxyz are v(4,5), w(6,5), x(6,7), y(…

Question

challenge the vertices of pentagon vwxyz are v(4,5), w(6,5), x(6,7), y(5,9), and z(4,7). graph vwxyz and vwxyz, its image after a translation 10 units left and 2 units down. then use the grid lines to estimate the distance between v and v. compare vwxyz and vwxyz. choose the correct graph below a. image b. image c. image

Explanation:

Step1: Find translated V'

Original $V(4,5)$. Translation: 10 left, 2 down.
New coordinates: $V'(4-10, 5-2) = (-6, 3)$

Step2: Calculate distance V to V'

Use distance formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Substitute $V(4,5), V'(-6,3)$:
$d=\sqrt{(-6-4)^2+(3-5)^2}=\sqrt{(-10)^2+(-2)^2}=\sqrt{100+4}=\sqrt{104}\approx10.2$

Step3: Verify correct graph

Original pentagon has points in the first quadrant. Translating 10 left and 2 down moves the figure to the left of the y-axis, matching Option A.

Answer:

A. The correct graph is Option A, and the distance between V and V' is $\sqrt{104}$ units (or ~10.2 units)