Question

1. $-\frac{1}{2}(8x + 8)=0$ check si

Explanation:

Step1: Expand the equation

$-\frac{1}{2}(8x + 8)=0$ can be expanded to $-\frac{1}{2}\times8x-\frac{1}{2}\times8 = 0$, which simplifies to $-4x-4 = 0$.

Step2: Isolate the variable term

Add 4 to both sides of the equation: $-4x-4 + 4=0 + 4$, resulting in $-4x=4$.

Step3: Solve for x

Divide both sides by - 4: $\frac{-4x}{-4}=\frac{4}{-4}$, so $x=-1$.

Step4: Check the solution

Substitute $x = - 1$ into the original equation: $-\frac{1}{2}(8\times(-1)+8)=-\frac{1}{2}(-8 + 8)=-\frac{1}{2}\times0 = 0$.

Answer:

$x=-1$