QUESTION IMAGE
Question
complete the following statement. use the integers that are closest to the number in the middle.
□ < -√8 < □
Step1: Find the range of $\sqrt{8}$
We know that $2^2 = 4$ and $3^2=9$. Since $4<8 < 9$, taking square roots (and since square root is an increasing function for non - negative numbers), we have $2<\sqrt{8}<3$.
Step2: Find the range of $-\sqrt{8}$
When we multiply an inequality by a negative number, the direction of the inequality sign changes. So, multiplying the inequality $2<\sqrt{8}<3$ by $- 1$, we get $-3<-\sqrt{8}<-2$.
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$-3 < -\sqrt{8} < -2$