Question

complete the table:
$f(r) = r^2 + 3r$

$r$	$f(r)$
-2
0
2

Explanation:

Step1: Substitute $r=-4$

$f(-4) = (-4)^2 + 3(-4) = 16 - 12$

Step2: Substitute $r=-2$

$f(-2) = (-2)^2 + 3(-2) = 4 - 6$

Step3: Substitute $r=0$

$f(0) = (0)^2 + 3(0) = 0 + 0$

Step4: Substitute $r=2$

$f(2) = (2)^2 + 3(2) = 4 + 6$

Answer:

$r$	$f(r)$
-2	-2
0	0
2	10